Question

The length of a rectangle is 7 m more than its breadth. If its perimeter is 50 m, find the length

and breadth of the rectangle.

Answer 1

Let assume Breadth =x

Then Length =x+7

Perimeter of rectangle =2(l+b)

50=2(x+7+x)

50=2(2x+7)

50/2=2x+7

25=2x+7

2x=25-7

2x=18

X=18/2

X=9


Breadth =9m
Length =9+7=16m


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Answer 2

ANSWER
.........

LET THE BREADTH = Y

THEREFORE THE Y + 7

= PERIMETER OF THE RECTANGULAR SHAPE
= 2 * L + B



= 50 = 2 ( Y + 7 + Y)

= 50 = 2 ( 2Y + 7)


= 50 / 2 = 2Y + 7


= 25 = 2Y + 7


2Y = 25 - 7


2Y = 18


Y = 18 / 2


Y = 9