The length of a rectangle is greater than its breadth by 3m. If its area be 10 sq. m, find the perimeter.
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Answered by
48
Let breadth = x
Length = x +3
Area of rectangle =10 Sq m
Perimeter =?
Area of rectangle = length × breadth
10 = ( x )( x +3)
10= x ^2+3x
x ^2+3x -10=0
(x+5)(x-2)=0
x=2 or -5
Length or breadth won't be in negative values
Therefore x =2
Breadth=2
Length =2+3=5
Perimeter =2 (l+b)
=2 (2+5)
=2×7
=14 m
Length = x +3
Area of rectangle =10 Sq m
Perimeter =?
Area of rectangle = length × breadth
10 = ( x )( x +3)
10= x ^2+3x
x ^2+3x -10=0
(x+5)(x-2)=0
x=2 or -5
Length or breadth won't be in negative values
Therefore x =2
Breadth=2
Length =2+3=5
Perimeter =2 (l+b)
=2 (2+5)
=2×7
=14 m
tamilking883:
that's correct
Answered by
2
the answer is 14
Step-by-step explanation:
the answer is 14
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