Question

the length of a rectangular field is 8 M less than twice its breadth if the perimeter of the rectangle field is 56 metres find its length and breadth

Answer 1

Let the Breadth be a

Length = 2a - 8

Perimeter = 2 ( Length + Breadth)

=> 56 = 2 ( a + 2a - 8)

=> 28 = 3a - 8

=> 3a = 36

=> a = 12

Breadth = 12 cm

Length = 2(12) - 8 = 16 cm

Answer 2

hiii!!!

here's ur answer...

ATQ, the length of the rectangular field is 8m less than twice it's breadth.

let the breadth of the rectangular field be x.

therefore length of the rectangular field = 2x - 8

given the perimeter of the rectangular field = 56m

==> 2 ( l + b ) = 56m

==> 2 ( 2x - 8 + x ) = 56m

==> 3x - 8 = 56/2

==> 3x - 8 = 28

==> 3x = 28 + 8

==> 3x = 36

==> x = 36/3

==> x = 12

hence, breadth of the rectangular field = x = 12m

length of the rectangular field = 2x - 8 = (2×12)-8 = 24 - 8 = 10m = 16m

hope this helps...!!!