the length of a rectangular hall is 5 m more than its breadth. If the area of the hall is 594 meter square, find its perimeter.
Answers
Answered by
119
Let the breadth be x and length be x+5
Area of rectangle =length * breadth
594= x(x+5)
594= x²+5x
0=x²+5x-594
0=x²+(27-22)x-594
0=x²+27x-22x-594
0=x(x+27)-22(x+27)
0=(x-22)(x+27)
Then x=22 OR x=-27
Taking positive value of x,
x=22=breadth and then
Length =22+5=27
Perimeter of rectangle =2(l+b)
Perimeter of rectangle =2(22+27)
Here, perimeter of rectangle =2*49
Here, perimeter of rectangle =98m
I hope this much will help you
Area of rectangle =length * breadth
594= x(x+5)
594= x²+5x
0=x²+5x-594
0=x²+(27-22)x-594
0=x²+27x-22x-594
0=x(x+27)-22(x+27)
0=(x-22)(x+27)
Then x=22 OR x=-27
Taking positive value of x,
x=22=breadth and then
Length =22+5=27
Perimeter of rectangle =2(l+b)
Perimeter of rectangle =2(22+27)
Here, perimeter of rectangle =2*49
Here, perimeter of rectangle =98m
I hope this much will help you
Answered by
5
Answer:
thank for your answer.............
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