Question

the length of a second pendulum where g is 980 cm/s2 is​

Answer 1

Answer:

Explanation:

We know that the time period of a simple pendulum is 2 sec

Given value of g is 980 cm/s^2

T = π  $\sqrt{l/g}$

⇒2 =  2 * 3.14 $\sqrt{{l/980}$

⇒ 1 /3.14 = $\sqrt{l/980}$

⇒ (1 /3.14)^2 = l/980 (taking the square root to the other side which makes it square)

⇒ 980 / 3.14 * 3.14 = l

l ≅ 99.2 cm