The length of an aluminum bar of length 80cm increases by 1mm on heating. What is the final temperature of the bar if it was initially at temperature 20°c.
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Δℓ / ℓₒ = αΔT
α = linear thermal expansion coefficient of steel = 24 x 10 ̄ ⁶ / °C
1 / 800 = 24 x 10 ̄ ⁶(ΔT)
=> ΔT = 10⁶ x [1/(24x800)] = 52.08333 °C
final T = 72.08333 °
α = linear thermal expansion coefficient of steel = 24 x 10 ̄ ⁶ / °C
1 / 800 = 24 x 10 ̄ ⁶(ΔT)
=> ΔT = 10⁶ x [1/(24x800)] = 52.08333 °C
final T = 72.08333 °
Answered by
1
The Cofficiant of linear expansion is not given so i m take the standard values for aluminum Cofficiant of linear expansion =25x10^-6
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Check the solution in pic
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