Question

The length of each side of a cube is halved.Find the ratio of are of original cube to new cube.

Answer 1

Answer:

8:1 if the ratio is of volume

Step-by-step explanation:

4:1 if the ratio is of area

hope this answer is helpful to you

Answer 2

Question :

The length of each side of a cube is halved. Find the ratio of area of original cube to new cube.

Solution :

Let the side of cube be ' x ' .

Area of cube = 6 × $\large{\mathrm{ x^2 }}$

Side of new cube = $\huge{\mathrm{ \frac{x}{2} }}$

Area of new cube = 6 × $\huge{\mathrm{ \frac{x}{2} }}$ ×$\huge{\mathrm{ \frac{x}{2} }}$

Now, divide the area of first and second cube =

6×$\large{\mathrm{ x^2}}$ ÷ 6× $\huge{\mathrm{ \frac{x}{2} }}$ $\huge{\mathrm{ \frac{x}{2} }}$

$\huge{\mathrm{ \frac{6×a×a×2×2}{6×a×a} }}$

= 4 : 1 .

Hence, ratio = 4 : 1 .