Question

the length of hypotenuse of isosceles right-angled triangle is 10 cm. find its perimeter. (use 2^1/2 = 1.414

Answer 1

↑ Here is your answer ↓
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Two sides of an isosceles triangle are equal, so let those two sides be 'x'

The third side will be the hypotenuse,

$x^2 + x^2 = 10^2$

$2x^2 = 100$

$x^2 = 50$

$x = \sqrt{50} cm$

Time to find the perimeter!

$\sqrt{50} + \sqrt{50} + 10$

$= 24.1421356237$

Answer 2

Answer:

25 cmsq.

Step-by-step explanation: in triangle ABC right angled at B,

                     let AB = BC = x

          so, by pythagorans theorm

            H sq. = P sq. + B sq.

             10 sq. = x sq. + x sq

             100 cm = 2x sq.

              100/2 = x sq.

                50 = x sq

               root under 50 = x

                    5root2 = x

 therefore,

           area of triangle ABC = 1/2 * b * h

                                             = 1/2 * x * x

                                             = 1/2 * 5root2 * 5root2

                                             = 1/2 * 50

                                             = 25 cmsq.