Question

The length of one of the diagonals of a field in the form of a quadrilateral is 40 m. The
perpendicular distances of the other two vertices from this quadrilateral are 12 m and 9 m.
Find the area of the field.​

Answer 1

Answer:

$420m^3$

Step-by-step explanation:

It is given that three of length 9m, 40m and 12m are present

let them be s1, s2, s3

From the question, it is clear that   s1 ⊥ s2   and   s3 ⊥ s2    or   s1 parallel to s3

So,

$area=(side_1+side_2)*(height/2)\\=\frac{s1+s3}{2}*s2\\=\frac{9+12}{2}*40m^2\\=21*20m^2$