the length of rectangle is three times than its width.the perimeter is 56m.find the length.
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Answered by
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let the breadthth of the rectangle be = x
so the length will be 3x
perimeter=56m
A.T.Q.
perimeter of rectangle=2(l+b)
2(x+3x)=56m
2x +6x=56m
8x =56m
x=56/8
x=7
breadth=7m
length=3x
=3×7=21.
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Viresh
so the length will be 3x
perimeter=56m
A.T.Q.
perimeter of rectangle=2(l+b)
2(x+3x)=56m
2x +6x=56m
8x =56m
x=56/8
x=7
breadth=7m
length=3x
=3×7=21.
hope it helps you
thanks
mark as brainliest too
Viresh
Answered by
0
Let the length be x
We know length is 3 times it's width and hence,
Width= x/3
Now perimeter = 2(length + width) =56
Putting values, 2(x + x/3) = 56
(4/3)*x = 28
x= 28*3/4 = 21m
Hence it's length is 21m.
If this helps you, kindly mark it as Brainliest :)
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