Question

the length of the legs of an isosceles triangle is 4 meters more than its base. if the perimeter of the triangle is 44 meters find the length of the sides of the triangle.​

Answer 1

Answer:

Let the length of the base be x cm

Length of other two equal sides = 2(x+4)

=2x+8

Perimeter of triangle = sum of all three sides

44 m = 2x+8 +x

44-8= 3x

36/3=x

12m=x

Length of other two sides= 12+4

=16m

Length of the sides of triangle are 12,16 and 16 m

Answer 2

GiveN:-

• The length of the legs of an isosceles triangle is 4 meters more than its base.
• Perimeter of the triangle = 44 m.

To FinD:-

The length of the sides of the triangle.

SolutioN:-

• Let us assume that the base is "x" m.
• So, length of the legs of the Isosceles triangle is "x + 4" m because it is 4 m more than the base.

We know that,

Isosceles triangle is a triangle whose two sides are equal and the third side is different.

So,

• All sides in a triangle sum upto its perimeter.
• Let the three sides be a, b, c.

☯ According to the question,

➡ a + b + c = Perimeter

where,

• a = (x + 4) m
• b = (x + 4) m
• c = x m
• Perimeter = 44 m

Substituting the values in the equation,

➡ (x + 4) + (x + 4) + x = 44

➡ x + 4 + x + 4 + x = 44

➡ 3x + 8 = 44

➡ 3x = 44 - 8

➡ 3x = 36

➡ x = 36/3

➡ x = 12

The sides are :

1. a = x + 4 = 12 + 4 = 16 m
2. b = x + 4 = 12 + 4 = 16 m
3. c = x = 12 m

The length of three sides of the isosceles triangle are 16 m, 16 m, 12m.

VerificatioN:-

➡ 16 + 16 + 12 = 44

➡ 44 = 44

➡ LHS = RHS

• Hence verified.