The length of the minute hand of a clock is 8cm.find the distance traveled by its outer end in 15 minutes
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Given
Length of minute hand =8cm
Angle created by minute hand in 15min
=360/60 x15
=90°
Theta (@)=90
Distance coverd will be length of arc created by minute hand in 15 or 90°
Distance =@/360 x 2 pi r
R=8cm (length of minute hand)
=90/360 x 2 x 22/7 x 8
=1/4 x2x22/7x8
=2x22/7x2
=4x22/7
=88/7 cm
=12.57cm
This is ur ans hope it will help you in case of any doubt comment below
Length of minute hand =8cm
Angle created by minute hand in 15min
=360/60 x15
=90°
Theta (@)=90
Distance coverd will be length of arc created by minute hand in 15 or 90°
Distance =@/360 x 2 pi r
R=8cm (length of minute hand)
=90/360 x 2 x 22/7 x 8
=1/4 x2x22/7x8
=2x22/7x2
=4x22/7
=88/7 cm
=12.57cm
This is ur ans hope it will help you in case of any doubt comment below
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