Question

the length of the parallel sides of a Trapezium are 16 cm and 12 CM. if the area of the trapezium is 140 square centimetre then what is the distance between those two sides?​

Answer 1

Answer:

10cm

Step-by-step explanation:

AB=12CM DC=16CM

AREA OF TRAP.=1/2×(AB+DC)×H

140 =1/2×12+16×H

140=1/2×28×H

140×2/28=H

10CM=H

Answer 2

Answer :

Distance between the Ⅱ sides of the trapezium(h) = 10 cm

Step - by - step explanation:

In the trapezium ABCD,

• Length of AB = 12 cm
• Length of CD = 16 cm
• Area of the trapezium = 140 cm²
• Distance between its Ⅱ sides/height of the trapezium = h

$\hrulefill$

We know,

☛ $\bold{Ar_{trapezium}=\frac{1}{2}\times{}(a+b)h}$

Applying the formula for the given question,

☛ $\bold{140=\frac{1}{2}\times{}(12+16)\times{}h}$

☛ $\bold{140=\frac{1}{2}\times{}28\times{}h}$

☛ $\bold{140=\frac{1}{2}\times{}28h}$

☛ $\bold{140=14h}$

☛ $\bold{h=\frac{140}{14}}$

☛ $\bold{h=10\:cm}$

∴ Distance between the parallel sides of the trapezium = 10cm