Question

the length of the rectangular field given in the figure is two times its width. the perimeter of the field is 180m. find the dimensions of the field

Answer 1

Answer:

Step-by-step explanation:

let the width of the rectangular field be x

therefore , length = 2x

perimeter of the field  = 180m

2(length +breadth) = 180

2(2x+x)=180

2*3x  =180

6x=180

x=30

width = 30m

length = 60m

Answer 2

Answer: 60m×30m

Step-by-step explanation:

Given:

Perimeter of the field = 180m

length of the rectangular field is two times its width.

Let the width be 'x' m.

Then, length ='2x' m.

Now, perimeter of the rectangle = 2(l+b)

= 2(x+2x)

= '6x' m

6x = 180

x = 180/6

x = 30

Hence, length = 2x = 2×30 =60m

width = x = 30 m

Hope it helps!