The line joining mid-points of two chords of a circle passes through the centre. Prove that the chords are parallel
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when the line divides both the chords into 2 equal halves then it means that it is perpendicular to both the chords (theorm of circle states that if a line segment bisects a chord than it is also perpendicular to it)
so by alternate int. angles property ( as both will be 90°) the 2 lines will be paralell
so by alternate int. angles property ( as both will be 90°) the 2 lines will be paralell
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for any chord, a line passing through midpoint and center is perpendicular bisector from center to the chord
(proof by congruency of 2 sides and equal angles)
so the if the same line passes through both the midpoints thethe line is perpendicular bisector for both the lines
so 90° at both ends
hence parallel
(proof by congruency of 2 sides and equal angles)
so the if the same line passes through both the midpoints thethe line is perpendicular bisector for both the lines
so 90° at both ends
hence parallel
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