Question

- The line passing through (-2,5) and (6,b) is perpendicular to the line 20x + 5y = 3. Find b?

Answer 1

the equations of the line passing through (-2,5) and perpendicular to the line 20x+5y=3 is ,
5x -20y+C=0
put (-2,5)
5(-2) -20(5) +C =0
-10-100+C=0
C=110.
the equation is 5x-20y +110=0.
it also passes through the point (6,b)
so, put in equation
we get ,
5(6) -20(b) +110=0
30 -20b +110=0
-20b +140=0
-20b = -140
so, b is 7

Answer 2

◆ Straight Lines ◆

Hey !!

Check the attachment.
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