The line segment AB joining the points A ( 2 , -4 ) and B ( 5 , 2 ) is trisected at the point C ( 3, a) and D ( b, 0 ) . Find the values of a and b
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Answer:
Ans: a=-2 , b=0
Step-by-step explanation:
In line segment AB, AC=CD=BD.( AB is trisected).
AC:BC=1:2=m:n
A (2,-4) B (5,2)C (3,a)
Using section formula and equating y cordinates.
a=(2-8)/3=-2
AD:DB=2:1=m:n
A (2,-4) B (5,2) D (b,0)
Using section formula and equating x coordinates:
b=(4-4)/3=0
therefore, a=-2, b=0.
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