The locus of the point which is equidistant from the points (-2,2)and (3,0) is
Answers
Given : points (-2,2)and (3,0)
To find : equation of locus of the points equidistant from the points
Solution:
locus of the points equidistant from the two points is perpendicular bisector of line join the point
Mid point of A ( -2 , 2) & B ( 3 , 0)
= ( - 2 + 3)/2 , ( 2 +0)/2
= 1/2 , 1
Slope of AB = ( 0 - 2)/(3 - (-2)) = -2/5
=> Slope of perpendicular bisector = 5/2
Equation of locus of the points equidistant from the two points
as slope = 5/2 and passes though mid point (1/2 , 1)
is y - 1 = (5/2 )(x - 1/2)
=> 4y - 4 = 10x - 5
=>10x = 4y + 1
equation of locus of the points equidistant from the points (-2,2)and (3,0) is 10x = 4y + 1
Learn more :
A(2, 4) and B(5, 8), find the equation ofthe locus of point P such ...
brainly.in/question/13789388
Find The Equation Of The Locus Of A Point P The Square Of Whose ...
brainly.in/question/11144004
