The magnetic flux through a coil perpendicular to its plane and directed into paper is varying according to the relation ∅=5t2+10t+5 milliweber. Calculate the EMF induced in the loop at t = 5 sec.
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Given :
Magnetic flux through perpendicular to coil is ∅=5t²+10t+5
milliweber
To Find : EMF induced in loop at
t = 5 seconds
Solution :
•According to Faraday's second law:
Magnitude of induced EMF is directly proportional to the rate of change of magnetic flux linked with the conductor coil.
=> EMF = |d∅/dt |
•Now, ∅ = 5t²+10t+5
d∅/dt = 10t + 10
At t = 5 seconds
d∅/dt = 10(5) +10
d∅/dt = 50 + 10
d∅/dt = 60
EMF = 60 mV
•Hence , Induced EMF in coil at t= 5 seconds is 60 mV
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