Question

The magnitude of two vectors are 3 and 4,and their scalar product is 8.find the angle between the vectors

Answer 1

Let two vectors be supposed a and b,

Then,

|a|=3 & |b|=4

a->.b->=6

Then,

α=cos^-1(6/(4*3)

Or, α=cos^-1(1/2)

.°.α=60°

This is the best answer.hope it helps you.

Answer 2

hii mate!

Let two vectors be supposed a and b,

Then,

|a|=3 & |b|=4

a->.b->=6

Then,

α=cos^-1(6/(4*3)

Or, α=cos^-1(1/2)

↔.α=60°

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hope it helps !!