Question

The mass of an electron is 9.1×10^-31 kg. If its kinetic energy is 3.0×10^-25 J, Calculate it's wavelength.

NEED CONTENT QUALITY ANSWER

Answer 1

$\color{red}{Here\:is\:your\: answer}$ ☺☺

------------------------------------------------------------------
------------------------------------------------------------------

$<marquee>Please see the refer attachment$

------------------------------------------------------------------
------------------------------------------------------------------

$\color{blue}{Hope\:it\:helps\:you}$
$\color{green}{Thank\:you}$

Answer 2

Answer:

The wavelength of an electron is 893.1 nm.

Explanation:

Kinetic energy of the electron = K.E = $3.0\times 10^{-25} J$

Mass of an electron = m = $9.1\times 10^{-31} kg$

Kinetic energy is given by :

$K.E=\frac{1}{2}mv^2$

$v=\sqrt{\frac{2\times K.E}{m}}$

de-Broglie wavelength is given by:

$\lambda =\frac{h}{mv}=\frac{h}{\sqrt{2\times K.E\times m}}$

where,

$\lambda$ = wavelength of electron

h = Planck's constant = $6.6\times 10^{-34}Js$

m = mass of electron = $9.1\times 10^{-31}kg$

v = velocity of electron (to be calculated from kinetic energy)

On substituting the values:

$\lambda =\frac{6.6\times 10^{-34}Js}{\sqrt{2\times 3.0\times 10^{-25} J\times 9.1\times 10^{-31}kg}}$[/tex]

$\lambda =0.8931\times 10^{-9} m=893.1 nm$

The wavelength of an electron is 893.1 nm.