Question

the mass of bucket containing water is 10kg .what is the work done in pulling up the bucket from a well of depth 10m if water is pouring out at a uniform rate from a hole in it and there is loss of 2kg of water from it while it reaches the top (g=10m/s Square)

Answer 1

I think it may be 800 joules
mass =10 kg
g=10 m/s
h=10 m
work done=mgh
but there is loss of 2 kg constantly therefore
mass =10-2=8kg
now,
work done=mgh
=> 8×10×10
=> 800 joules

Answer 2

Answer:

900 j

Explanation:

Gravitational force on bucket at starting position =mg=10 x 10 =100 N

Gravitational force on bucket at final position=8 x 10 = 80 N

So the average force through out the vertical motion

100+80/2=90N

Work done = force x displacement

                    =90 x 10 =900 j

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