Question

The coordinates of the end points of a line segment PQ are P(3,7) and Q (11,-6).Find the coordinates of the point R on the y axis such that PR = QR

Answer 1

P(3,7)  Q(11,-6)

We have the point R on the y-axis,

 R (0,y)

Such that:

PR = QR

PR= sqrt[(3-0)^2 + (7-y)^2]

QR= sqrt[(11-0)^2 + (-6-y)^2

sqrt[(9+(7-y)^2]= sqrt[121 + (-6-y)^2]

Square both sides:

9+ (7-y)^2 = 121 + (-6-y)^2

Open brackets:

 9 + 49 -14y + y^2 = 121+36 +12y + y^2

 58 -14y = 157 + 12y

26y = -99

 y= -99/26

 R (0, -99/26)