Question

The mass of Cao that shall be obtained by heating 20
kg of 90% pure lime-stone (CaCO3) is
(a) 11.2 kg
(b) 8.4 kg
(c) 10.08 kg
(d) 16.8 kg​

Answer 1

Answer:

95% of 2000 kg = 1900 kg Limestone

1 kg = 1000 grams

1900 kg = 1000 * 1900 = 1900000 grams

equation so formed is

Ca CO3 ===> CaO + CO2

1 mole of lime stone =

Ca = 40

C = 12

O3 = 3 * 16 = 48

! mole of limestone = 40 + 12 + 48 = 100 grams / mole

1 mole Lime stone = 100 grams

x mole Lime stone = 1900000

100x = 1900000

x = 19000 moles

1 mole CaO = 40 + 16 = 56 grams / mole

19000 mole CaO = x

x = 19000 * 56 = 1064000 grams or

x = 1064 kg

Explanation:

here is the answer