Question

The mass of potassium dichromate crystals required to oxidise 750cm³ of 0.6m mohrsalt solution is

Answer 1

Hello! 

We have the following data: 

M (molarity or Molar Concentration) = 0.6 M (Mol/L)
m1 (mass of the solute k2cr2o7) = ? (in grams) 
V (volume) = 750 cm³ → 0.75 L
MM (Molar mass of potassium dichromate k2cr2o7)
K ≈ 2*39 ≈ 78 u
Cr ≈ 2*52 ≈ 104 u
O ≈ 7*16 ≈ 112 u
-----------------------------------------
MM (Molar mass  k2cr2o7) ≈ 78 + 104 + 112 ≈ 294 g/mol

We apply the data to the molar concentration formula, see:

$M = \dfrac{m_1}{MM*V}$

$0.6 = \dfrac{m_1}{294*0.75}$

$0.6 = \dfrac{m_1}{220.5}$

$m_1 = 0.6*220.5$

$\boxed{\boxed{m_1 = 132.3\:g}}\end{array}}\qquad\checkmark$

I Hope this helps, greetings ... DexteR!

Answer 2

Answer:

Explanation:hope it's helpful for you guys.......