Question

The mass of water is 70.0 g. What is the energy required to heat a beaker of water at 18 degrees C to boiling?

Answer 1

Answer : The energy required to heat a beaker of water at $18^oC$ to boiling is, 21976.5 J

Solution :

Formula used :

$Q=m\times c\times \Delta T=m\times c\times (T_{final}-T_{initial})$

where,

Q = heat required = ?

m = mass of water = 70 g

c = specific heat of water = $4.186J/g^oC$      

$\Delta T=\text{Change in temperature}$  

$T_{final}$ = final temperature = $100^oC$

$T_{initial}$ = initial temperature = $18^oC$

Now put all the given values in the above formula, we get the heat required for water.

$Q=70 g\times 4.186J/g^oC\times (100-25)^oC$

$Q=21976.5J$

Therefore, the energy required to heat a beaker of water at $18^oC$ to boiling is, 21976.5 J

Answer 2

Answer:

The answer is q = 24,000 J

Explanation: