Question

The maximum and minimum values of the function y = x3 - 3x2 + 6 are
(2) 6,0
(3) 6, 2
(4) 4,2
(1) 2,0​

Answer 1

Answer:

(2,6)

Explanation:

y=x^3-3x2+6

dy/dx=3xcube-6x

for points of minimum and maximum dy/dx=O

3x^2-6x=0

x(3x-6)=0

x=0,3x-6=0

x=6/3

x=2/3

x=0,y(0)=6

at x=2

y(2)= (2)^3-3(2)^+6

=8-12+6

8-2=6

(maximum, minimum)=(2,6)