Question

The maximum value of index of refraction of a material of a prism which allows the passage of light

Answer 1

Solution:

Given:

=> Velocity of sound in gas at 27°C = 330 m/s.

To Find:

=> Velocity at 327°C.

Let velocity at 327°C be x,

So,

\sf{\implies \dfrac{27}{330}=\dfrac{327}{x}}⟹33027=x327

\sf{\implies \dfrac{330 \times 327}{27} = x}⟹27330×327=x

\sf{\implies x = 3996.6\;m/s}⟹x=3996.6m/s

{\boxed{\boxed{\bf{So,\;velocity\;at\;327^{\circ}C=3996.6\;m/s}}}}So,velocityat327∘C=3996.6m/s