Question

The rate constant of a reaction at 290k was found to be 3.2×10^-3s^-1when the temperature is raised to 310k it will be about

Answer 1

Explanation:

K1= 3.2×10^-3 sec

temp changes from 290 to 310 k that is by 20°C

for every 10°C the rate constant is nearly double i.e

becomes 2^1= 2K1

for 20°C the rate constant becomes Four times i.e

2^2= 4K1

therefore at 310 k

K2=4K1

K2= 4×3.2×10^-3

K2 = 12.8 ×10^-3 sec