Biology, asked by ROSHANS5734, 1 year ago

The mean extracellular cellulase activity of 7 bacillus strains isolated from soil was determined to be 12 iu/ml. A new hyper-producing bacillus isolate was found to have an extracellular activity of 36 iu/ml. If equal volumes of the supernatants of all 8 strains are mixed together, the cellulase activity of the solution will be

Answers

Answered by tushardhamale
8

Answer:

15

Explanation:

Mean cellulase activity for 7 strains is 12 IU/mL.

Thus, we assume each strain can produce and contribute 12 IU/mL.

And

The 8th strain produces 36 IU/mL.

Now if equal amounts of supernatants from all 8 strains are mixed together, then the resulting solution will have mean of cellulase activity of all 8 strains.

It is calculated as

=(12+12+12+12+12+12+12+36)/8 = 15

Thus, cellulase activity of the solution will be 15 IU/ mL

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