the mean of 20 observation is 31 later on it was detected that an observation was taken as 52 instead of 25 find the correct mean
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Let Observations be x1,x2,.........................x20
We are given, x1+x2+.............+x20/20 = 31
so, x1+x2+.................x20 = 620
Let incorrect observation be x20
so, x1+x2+x3+..........x19 + 52 = 620
so, x1+x2+x3...............x19 = 568
Correct mean = x1+x2+x3+..............x19 + 25/20
= 568 + 25/20
= 29.65
Hence, Correct mean is 29.65
We are given, x1+x2+.............+x20/20 = 31
so, x1+x2+.................x20 = 620
Let incorrect observation be x20
so, x1+x2+x3+..........x19 + 52 = 620
so, x1+x2+x3...............x19 = 568
Correct mean = x1+x2+x3+..............x19 + 25/20
= 568 + 25/20
= 29.65
Hence, Correct mean is 29.65
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