Question

the mean of five numbers is 30. if one number is excluded their mean becomes 28. find the excluded number

Answer 1

(a+b+c+d+e)/5=30----------(1)
GIVEN ,
(a+b+c+d)/4=28
a+b+c+d=112
SUBSTITUTING IT IN EQUATION (1)
(112+e)=150
e=38
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Answer 2

Given that mean of 5 number is 30.

Let the sum of 5 numbers be x. Then we can represent the above statement as

⇒ x/5 = 30

⇒ x = 150

IF one number is excluded then the mean becomes 28.

Let the sum of the 4 numbers be y, Then we can represent the above statement as

⇒ y/4 = 28

⇒ y = 112

Let the excluded number be z.

Now the excluded number can be obtained by subtracting 'sum of 4 numbers (y)' from 'sum of 5 numbers (x)'

⇒ z = x - y

⇒ z = 150 -112

⇒ z = 38

∴ The excluded number is 38.