The mean of the following frequency distribution is 50 find the missing frequencies f1 and f2
Class 0-20 0-40 40-60 60-80 80-100 total
17 f1 32 f2 19 120
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The value of f1 and f2 are 28 and 24.
Solution:
The sum of the frequency is equal to 120, so the sum be 17+f1+32+f2+19 = 120,
which means the sum of f1+f2 = 120 – 68
f1 + f2 = 52.
Now for the mean of the frequency we can say that that means
The sum of is equal to
50
we get the another equation for f1 and f2 i.e. 2520=30f1+70f2
Now equating 2520=30 f1+70 f2 and f1 + f2 = 52.
We get the value of f1 as 28 and f2 as 24.
Therefore, the value of f1 and f2 is equal to 28 and 24 respectively.
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