The mid-point of segment AB is the point P (0, 4). If the coordinates of B are (−2, 3) then the coordinates of A are
A. (2, 5)
B. (−2, −5)
C. (2, 9)
D. (−2, 11)
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by mid point section formula
X= X^1 + X^2/ 2 Y = Y^1 + Y^2/ 2
0 = X^1 - 2 / 2 4 = Y^1 +3/2
X^1-2 4×2 = Y^1+3
X^1= -2 8 = Y^1+3
Y^1 = 3+8
Y^1 = 11
si coordinates of A (-2,11)
X= X^1 + X^2/ 2 Y = Y^1 + Y^2/ 2
0 = X^1 - 2 / 2 4 = Y^1 +3/2
X^1-2 4×2 = Y^1+3
X^1= -2 8 = Y^1+3
Y^1 = 3+8
Y^1 = 11
si coordinates of A (-2,11)
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