Question

The minimum distance covered before attaining a
speed of 8 m/s starting from rest is nearly (u = 0.4)
(take g = 10 m/s2)
(1) 8 m
(2) 4 m
(3) 10 m
(4) 16 m​

Answer 1

Explanation:

V= U + at

t= V-U/a = 8-0.4/10 = 7.6/10= 0.76s

Distance covered in this time

X= ut + 1/2at^2

X = 0.4(0.76) + 1/2(10)(0.76)^2

X= 0.304+ 2.888

X= 3.2m