Question

The minimum molar mass of haemoglobin if it contains 0.335% of iron.

Answer 1

Answer:

To calculate the percentage of iron:

M amu of heamoglobin has iron=223.4

100 amu of heamoglobin has iron=223.4M×100

Equating to the given value,

223.4M×100=0.335

Solving for M,

M=223.40.335×100

=66686.57gmol−1, rounded to two decimal places.

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At some places the iron percentage in heomoglobin is given as 0.3335%. Using the published average atomic mass of iron as 55.847,