The minimum value of the function y=4x²+2
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MINIMUM VALUE WILL BE 0
AS 0*0*4 + 2=2
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Given function y=4x²+2
When the function attains it's minimum value,
dy/dx will be 0.
dy/dx = 0
=> d/dx(4x²+2) = 0
=> 8x = 0
=> x = 0
Thus, the function attains minimum value at x=0.
y(at x=0) = 4×0^2 + 2 = 2
Hence, minimum value of the function is 2.
When the function attains it's minimum value,
dy/dx will be 0.
dy/dx = 0
=> d/dx(4x²+2) = 0
=> 8x = 0
=> x = 0
Thus, the function attains minimum value at x=0.
y(at x=0) = 4×0^2 + 2 = 2
Hence, minimum value of the function is 2.
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