Question

The molal elevation constant of water is 0.51 the boiling point of 0.1 molal aquous nacl solution is nearly

Answer 1

The boiling point of solution is, $100.102^oC$

Explanation :

Formula used for Elevation in boiling point :

$\Delta T_b=i\times k_b\times m$

or,

$T_b-T^o_b=i\times k_b\times m$

where,

$T_b$ = boiling point of solution = ?

$T^o_b$ = boiling point of water = $100^oC$

$k_b$ = molal elevation constant of water = $0.51^oC/m$

m = molality  = 0.1 m

i = Van't Hoff factor = 2 (for NaCl electrolyte)

Now put all the given values in the above formula, we get:

$(T_b-100)^oC=2\times (0.51^oC/m)\times 0.1m$

$T_b=100.102^oC$

Therefore, the boiling point of solution is, $100.102^oC$

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