Question

The molar mass of a first member in a
homologous series is 28, then the molar
mass of third member in the series is ???​

Answer 1

Answer:

m of 1st memb. = 28 ..then m of 3rd memb. will be 28+14+14= 28+28=56..since in a homologous series molar mass increases to each succecive mem. by 14 units