Question

the mole percentage of oxygen in a mixture of 7.0gm of nitrogen and 8.0gm of oxygen is​

Answer 1

Answer:

mole percentage=(moles of oxygen/total no.of moles in mixture .)*100

moles of o2=8/32=1/4=0.25

moles of N2=7/28=1/4=0.25

so,

0.25/0.25+0.25=0.25/0.5=0.5*100=50%

so percentage of oxygen in mixture is 50%

hope so helpful.