Chemistry, asked by ni14920914tin, 5 months ago

The molecule IF7 takes a sp3d3 hybridisation. The F—I—F bond angle present in the molecule among the following are:
-60° and 180°
-72° and 90°
-60° and 72°
-60° and 90°

Answers

Answered by mullavasimm
1

Answer:

-72° and 90°

Explanation:

the lf7 have pentagonal bipyramidal geometry F molecule in the pentaginal plane have bond angle of -72° .and the vartical F which is perpendicular to the pentagonal molecule. which have 90° angle .

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