Question

the moment of inertia of a thin rod of mass m and length l about an axis passing through Its central and normal to its length is given by ml2/12 using theorem of parallel axes, find its moment of inertia about an axis passing through on end and normal to its length if l=1m and m=0.2kg

Answer 1

By parallel axis theorem
I = Ml²/12 + M(L/2)²
I = ML²/3
I = 0.2kg * 1/3
I = 0.066 kgm²