Question

the momentum of a photon of freequency v is a) h/c b)hc c) hv d) hv/c​

Answer 1

Solution:-

$\to \bf \: momentum(p) = p = \frac{h}{ \lambda}$

Where

$\bf \: h \to \: plank \: constant$

$\bf \: \lambda \: \to \: wavelength$

We know that

$\to \bf \: c = v \lambda$

where C => Speed of light

$\to \bf \: \lambda = ( \frac{c}{v} )$

$\bf Now \: put \: the \: value \: of \: \lambda \: on \: p \:$

We get

$\to \bf \: p = \frac{h}{ \lambda} \: = \frac{h}{ \frac{c}{v} } = \frac{hv}{c}$

$\boxed { \bf \blue {Answer : \: p = \frac{hv}{c} }}$