Question

the motion of a body falling from rest on in a medium is given by equation,dv/dt = 1-2v. the velocity at any time t is

Answer 1

Given-

(dv)/dt = 1-2v

dv (1/(1-2v) = dt

Now,

integrating both sides we get,

(-1/2)×ln(1- 2v) = t .....Zero initial conditions ,hence c=0

ln(1- 2v) = -2t

1 -2v = e^-2t

v = (1 - e^-2t)/2

This is the required velocity time relation

Answer 2

Answer:

hey,see the attachment.