Physics, asked by sivanigontu4276, 11 months ago

The motion of an object is given by x=23sin2(2−3t). This is a

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Answered by khushu33
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the position of an object at any time is given by the equation s(t)=3t^3-2t+4 find the equations of its velocity and its acceleration .(the...

the position of an object at any time is given by the equation s(t)=3t^3-2t+4 find the equations of its velocity and its acceleration .(the equation are to be in terms of t) Its velocity is given by v(t)= its acceleration is given by a(t)=

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MLEHUZZAH eNotes educator| CERTIFIED EDUCATOR

The velocity of the object is the derivative of its position function.

The acceleration of the object is the derivative of its velocity function.

s(t)=3t^3-2t+4

The derivative of a x^n is a n x^(n-1)

The derivative of c x is c

The derivative of a constant is 0

So:

v(t)=s'(t)=9 t^2 - 2

a(t)=v'(t)=18 t

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Answered by vedp06037
0

This is shm equation where A=23,W=6

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