Question

the. net electric force ona charge of+3microC at the midpoint on the line joining two charges of magnitude +2icroC and -2microC separated by the distance of 6mm is​

Answer 1

Answer:

$12 \times {10}^{3}$

Explanation:

Force due to both the charges are in same direction, so they add up.

$f1 = \frac{9 \times {10}^{9} \times 3 \times {10}^{ - 6} \times 2 \times {10}^{ - 6} }{ ({3 \times {10}^{ - 3} )}^{2} } = 6 \times {10}^{3}$

$f2 = \frac{9 \times {10}^{9} \times 3 \times {10}^{ - 6} \times 2 \times {10}^{ - 6} }{( {3 \times {10}^{ - 3} )}^{2} } = 6 \times {10}^{3}$

$f = f1 + f2 = 6 \times {10}^{3} + 6 \times {10}^{3} = 2 \times 6 \times {10}^{3} = 12 \times {10}^{3}$