Question

the no. of atom present in 16g of oxygen is​

Answer 1

Answer:

No. of moles = W/MM = N/Na

16/16 ×Na ×1 = N

N = Na

N = 6.022 × 10^23 atoms.

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Answer 2

Answer:

6.022×10^23 because of the mole concept as

oxygen has 1 atom of 16u which is treated as 16g in molar mass.