Question

the nth term of 3,7,11,15 is

Answer 1

The nth term of 3 , 7 , 11 , 15 is 4n - 1

Given : The progression is 3 , 7 , 11 , 15

To find : The nth term

Tip :

If in an arithmetic progression

First term = a

Common difference = d

Then nth term of the AP

= a + ( n - 1 )d

Solution :

Step 1 of 2 :

Write down the given progression

The given progression is

3 , 7 , 11 , 15

Step 2 of 2 :

Find the nth term of the progression

The given progression is an arithmetic progression

First term = a = 3

Common Difference = d = 7 - 3 = 4

The nth term

$\sf = a + (n - 1)d$

$\sf = 3 + (n - 1) \times 4$

$\sf = 3 + 4n - 4$

$\sf = 4n - 1$

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Answer 2

EXPLANATION.

Arithmetic sequences : 3, 7, 11, 15, . . . . .

As we know that,

General terms of an ap.

⇒ Tₙ = a + (n - 1)d.

Using this formula in this question, we get.

First term : a = 3.

Common difference : d = b - a : 7 - 3 = 4.

To find : Nth terms of an ap.

⇒ Tₙ = 3 + (n - 1)4.

⇒ Tₙ = 3 + 4n - 4.

⇒ Tₙ = 4n - 1.

∴ The Nth term of an ap : Tₙ = 4n - 1.