what is the result when ethanoic acid is reacted with NA2CO3?
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CH3-COOH + Na2CO3 = CH3-COONa + CO2 + H2O
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when the ethanoic acid reacts with carbonate sodium ethanoate with carbon dioxide and water is formed.
2CH3COOH + Na2CO3 ~~~ 2CH3COONa + CO2 + H2O
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2CH3COOH + Na2CO3 ~~~ 2CH3COONa + CO2 + H2O
#HOPE IT HELPS!!
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