Question

The number (256)^2 56 is obtained by raising (16)^16 to the power n. What is the value of n​

Answer 1

In this problem, we need to find out how many multiples of 4 lie between 10 and 250.

So, we know that the first multiple of 4 after 10 is 12 and the last multiple of 4 before 250 is 248. Also, all the terms which are divisible by 4 will form an A.P. with the common difference of 4.

So here,

First term (a) = 12

Last term (an) = 248

Common difference (d) = 4

So, let us take the number of terms as n

Now, as we know,

So, for the last term,

Further simplifying,

Therefore, the number of multiples of 4 that lie between 10

AM I CORRECT.

HOPE YOU GOT IT MY FRIEND

Answer 2

(1024)¹⁰²⁴=(16)¹⁶)n

=>(2¹⁰)¹⁰²⁴=(16)¹⁶n

=>(2)¹⁰²⁴⁰=(2⁴)¹⁶n

=>64n=10240

=n=160